Let $A$ and $B$ the two gases and given $\frac{T_{B}}{M_{A}} = 4.\frac{T_{B}}{M_{B}};$ where $T$ is the temperature and $M$ is molecular mass. If $C_{A}$ and $C_{B}$ are the $r.m.s.$ speed, then the ratio $\frac{C_{A}}{C_{B}}$ will be equal to

Question

Dr. Abubacker · Accepted Answer

(a) $\frac{T_{A}}{M_{A}} = 4\frac{T_{B}}{M_{B}} \Rightarrow \sqrt{\frac{T_{A}}{M_{A}}} = 2\sqrt{\frac{T_{B}}{M_{B}}}$
$\Rightarrow \sqrt{\frac{3RT_{A}}{M_{A}}} = 2\sqrt{\frac{3RT}{M_{B}}} \Rightarrow C_{A} = 2C_{B} \Rightarrow \frac{C_{A}}{C_{B}} = 2$

Q. Let $A$ and $B$ the two gases and given $\frac{T_{B}}{M_{A}} = 4.\frac{T_{B}}{M_{B}};$ where $T$ is the temperature and $M$ is molecular mass. If $C_{A}$ and $C_{B}$ are the $r.m.s.$ speed, then the ratio $\frac{C_{A}}{C_{B}}$ will be equal to

Explanation

Reviewed by Dr. Abubacker

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