Q. The root mean square velocity of a gas molecule of mass $m$ at a given temperature is proportional to
A) $m^{0}$
B) $m$
C) $\sqrt{m}$
D) $\frac{1}{\sqrt{m}}$
Explanation
(d) $v_{rms} = \sqrt{\frac{3kT}{m}} = v_{rms} \propto \frac{1}{\sqrt{m}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.