Q. A polyatomic gas with $n$ degrees of freedom has a mean energy per molecule given by ($N$ is Avogadro’s number)
A) $\frac{nkT}{N}$
B) $\frac{nkT}{2N}$
C) $\frac{nkT}{2}$
D) $\frac{3kT}{2}$
Explanation
(c) Mean kinetic energy per molecule $E = \frac{f}{2}kT = \frac{n}{2}kT$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.