Q. For an ideal gas
A) $C_{p}\ is\ less\ than\ C_{V}$
B) $C_{p}\ is\ equal\ to\ C_{V}$
C) $C_{p}\ is\ greater\ than\ C_{V}$
D) $C_{p} = C_{V} = 0$
Explanation
(c) $C_{p}\ is\ always\ greater\ than\ C_{V}\ $
$ie$, $C_{P} > C_{V}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.