Q. Two moles of monoatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is
A) $1.55\ R$
B) $2.10\ R$
C) $1.63\ R$
D) $2.20\ R$
Explanation
(b) Molar specific heat of the mixture at constant volume is
$C_{V} = \ \frac{n_{1}{C_{V}}_{1} + n_{2}{C_{V}}_{2}}{\left( n_{1} + n_{2} \right)}$
= $\frac{2\left( \frac{3}{2}R \right) + 3\left( \frac{5}{2}R \right)}{2 + 3} = 2.1\ R$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.