A flask of volume $10^{3}$ cc is completely filled with mercury at 0$℃$. The coefficient of cubical expansion of mercury is 180 $ imes 10^{- 6}℃^{- 1}$ and that of glass is$40 imes 10^{- 6}℃^{- 1}$. If the flask in now placed in boiling water at 100$℃$, how much mercury will overflow?

Question

A flask of volume $10^{3}$ cc is completely filled with mercury at 0$℃$. The coefficient of cubical expansion of mercury is 180 $	imes 10^{- 6}℃^{- 1}$ and that of glass is$40 	imes 10^{- 6}℃^{- 1}$. If the flask in now placed in boiling water at 100$℃$, how much mercury will overflow?

Dr. Abubacker · Accepted Answer

(b) Here, $V_{0} = 10^{3}\ cc$
$\gamma_{r} = 180 	imes 10^{- 6}℃^{- 1}\ $
g = $40 	imes 10^{- 6}℃^{- 1},\ \ t = 100℃$
$\gamma_{a}\  = \ \gamma_{r} - g = (180 - 40)10^{- 6}$
$V_{t} = V_{0}\left( 1 + 140 	imes 10^{- 6} 	imes 10^{2} ight)$
= $\left( 10^{3} + 14 ight)cc$
$	herefore$ Volume of mercury that will overflow
= $V_{t} - V_{0} = 14\ cc$

Q. A flask of volume $10^{3}$ cc is completely filled with mercury at 0$℃$. The coefficient of cubical expansion of mercury is 180 $\times 10^{- 6}℃^{- 1}$ and that of glass is$40 \times 10^{- 6}℃^{- 1}$. If the flask in now placed in boiling water at 100$℃$, how much mercury will overflow?

Explanation

Reviewed by Dr. Abubacker

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