Q. A gas at $27℃$ has a volume $V$ and pressure $P.$ On heating its pressure is doubled and volume becomes three times. The resulting temperature of the gas will be
A) $1800℃$
B) $162℃$
C) $1527℃$
D) $600℃$
Explanation
(c) $\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$
$T_{2} = \frac{P_{2}V_{2}}{P_{1}V_{1}}T_{1} = \frac{2}{1} \times \frac{3}{1} \times 300 = 1800K = 1527℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.