Q. Mean kinetic energy per degree of freedom of gas molecules is
A) $\frac{3}{2}kT$
B) $kT$
C) $\frac{1}{2}kT$
D) $\frac{3}{2}RT$
Explanation
(c) According to law of equipartion of energy, kinetic energy per degree of freedom of a gas molecule is $\frac{1}{2}kT$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.