Q. The pressure is exerted by the gas on the walls of the container because
A) It loses kinetic energy
B) It sticks with the walls
C) On collision with the walls there is a change in momentum
D) It is accelerated towards the walls
Explanation
(c) Pressure, $P = \frac{F}{A} = \frac{1}{A}.\frac{\mathrm{\Delta}p}{\mathrm{\Delta}t}\ \lbrack\mathrm{\Delta}p =$ change in momentum$\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.