Q. Air inside a closed container is saturated with water vapour. The air pressure is $p$ and the saturated vapour pressure of water is $\overline{p}$. If the mixture is compressed to one half of its volume by maintaining temperature constant, the pressure becomes

A) $2\left( p + \overline{p} \right)$
B) $\left( 2p + \overline{p}\ \right)$
C) $(\frac{p + \overline{p}}{2}$
D) $p + 2\overline{p}$
Explanation

(b) $P_{f} = 2p + \overline{p}$
Saturated vapour pressure will not change if temperature remains constant.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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