Q. The temperature of a piece of metal is increased from 27$℃$ to 84$℃$. The rate at which energy is radiated is increased to
A) Four times
B) Two times
C) Six times
D) Eight times
Explanation
(b) $\frac{E_{2}}{E_{1}} = \left( \frac{T_{2}}{T_{1}} \right)^{4}$
= $\left( \frac{273 + 84}{273 + 27} \right)^{4} = \left( \frac{357}{300} \right)^{4} = 2.0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.