A mixture of 2 moles of helium gas (atomic mass = $4\ amu$), and 1 mole of argon gas (atomic mass = $40amu$) is kept at $300K$ in a container. The ratio of the $rms$ speeds $\left\lbrack \frac{V_{rms}(helium)}{V_{rms}(argon)} \right\rbrack$ is

Question

Dr. Abubacker · Accepted Answer

(d) $\frac{{V_{rms}}_{He}}{{V_{rms}}_{Ar}} = \frac{\sqrt{\frac{3RT}{m_{He}}}}{\sqrt{\frac{3RT}{m_{Ar}}}} = \sqrt{\frac{m_{Ar}}{m_{He}}} = \sqrt{\frac{40}{4}} = \sqrt{10} \approx 3.16$

Q. A mixture of 2 moles of helium gas (atomic mass = $4\ amu$), and 1 mole of argon gas (atomic mass = $40amu$) is kept at $300K$ in a container. The ratio of the $rms$ speeds $\left\lbrack \frac{V_{rms}(helium)}{V_{rms}(argon)} \right\rbrack$ is

Explanation

Reviewed by Dr. Abubacker

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