Q. $CO_{2}(O - C - O)$ is a triatomic gas. Mean kinetic energy of one gram gas will be (If $N$-Avogadro’s number, $k$-Boltzmann’s constant and molecular weight of $CO_{2} = 44$)

A) $(3/88)NkT$
B) $(5/88)NkT$
C) $(6/88)NkT$
D) $(7/88)NkT$
Explanation

(d) Mean kinetic energy for $\mu$ mole gas $= \mu.\frac{f}{2}RT$
$\therefore E = \mu\frac{7}{2}RT = \left( \frac{m}{M} \right)\frac{7}{2}NkT = \frac{1}{44}\left( \frac{7}{2} \right)NkT$
$= \frac{7}{88}NkT\ \ \lbrack As\ f = 7\ and\ M = 44\ for\ CO_{2}\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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