(d) Mean kinetic energy for $\mu$ mole gas $= \mu.\frac{f}{2}RT$
$\therefore E = \mu\frac{7}{2}RT = \left( \frac{m}{M} \right)\frac{7}{2}NkT = \frac{1}{44}\left( \frac{7}{2} \right)NkT$
$= \frac{7}{88}NkT\ \ \lbrack As\ f = 7\ and\ M = 44\ for\ CO_{2}\rbrack$