Oxygen and hydrogen are at the same temperature $T$. The ratio of the mean kinetic energy of oxygen molecules to that of the hydrogen molecules will be

Question

Dr. Abubacker · Accepted Answer

(b) The mean kinetic energy for gas molecules
$E = \frac{3}{2}kT \Rightarrow E \propto T$
So, $\frac{E_{1}}{E_{2}} = \frac{T_{1}}{T_{2}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots(i)$
According to question both gases are at the same temperature $T$.
So, $\frac{E_{1}}{E_{2}} = \frac{T}{T} = \frac{1}{1}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E_{1}:E_{2} = 1:1$

Q. Oxygen and hydrogen are at the same temperature $T$. The ratio of the mean kinetic energy of oxygen molecules to that of the hydrogen molecules will be

Explanation

Reviewed by Dr. Abubacker

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