Q. At constant temperature on increasing the pressure of a gas by $5\%$ its volume will decrease by
A) $5\%$
B) $5.26\%$
C) $4.26\%$
D) $4.76\%$
Explanation
(d) $P \propto \frac{1}{V} \Rightarrow \frac{V_{2}}{V_{1}} = \frac{P_{1}}{P_{2}} = \frac{100}{105} \Rightarrow V_{2} = \frac{100}{105}V_{1} = 0.953\ V_{1}$
% change in volume $= \frac{V_{1} - V_{2}}{V_{1}} \times 100$
$= \frac{V_{1} - 0.953V_{1}}{V_{1}} \times 100 = 4.76\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.