A vessel contains 32 g of $O_{2}$ at a temperature $T$. The pressure of the gas is $p$. An identical vessel containing 4 g of $H_{2}$ at a temperature $2T$ has a pressure of

Question

Dr. Abubacker · Accepted Answer

(b) For first vessel, number of moles
$n_{1} = \frac{m_{1}}{M_{1}} = \frac{32}{32} = 1$
Volume=$V$, Temperature=$T$
$	herefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ p_{1}V = RT$ ..(i)
For second vessel number of moles
=$n_{2} = \frac{m_{2}}{M_{2}} = \frac{4}{2} = 2$
Volume=$V$, Temperature=2$T$
$	herefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ p_{2}V = 2R(2T)$ ...(ii)
From Eqs. (i) and (ii),
$p_{2} = 4p_{1} = 4\ p$

Q. A vessel contains 32 g of $O_{2}$ at a temperature $T$. The pressure of the gas is $p$. An identical vessel containing 4 g of $H_{2}$ at a temperature $2T$ has a pressure of

Explanation

Reviewed by Dr. Abubacker

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