Q. The mean kinetic energy of one mole of gas per degree of freedom (on the basis of kinetic theory of gases) is
A) $\frac{1}{2}\ k\ T$
B) $\frac{3}{2}\ k\ T$
C) $\frac{3}{2}\ R\ T$
D) $\frac{1}{2}\ R\ T$
Explanation
(d) The main kinetic energy of one mole of gas $n$ degree of freedom.
$E = \frac{n}{2}RT$
The mean kinetic energy of one mole of gas per degree of freedom.
$E^{'} = \frac{E}{n} = \frac{\frac{n}{2}RT}{n}$
$E^{'} = \frac{1}{2}RT$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.