Q. A diatomic gas molecule has translational, rotational and vibrational degrees of freedom. The $C_{P}/C_{V}$ is
A) 1.67
B) 1.4
C) 1.29
D) 1.33
Explanation
(d) Degree of freedom $f = 3$ (Translatory)+2(rotatory)+1(vibratory) = 6
$\Rightarrow \frac{C_{P}}{C_{V}} = \gamma = 1 + \frac{2}{f} = 1 + \frac{2}{6} = \frac{4}{3} = 1.33$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.