Q. A pressure cooker contains air at $1\ atm$ and $30℃.$ If the safety value of the cooler blows when the inside pressure $\geq 3\ atm,$ then the maximum temperature of the air, inside the cooker can be
A) $90℃$
B) $636℃$
C) $909℃$
D) $363℃$
Explanation
(b) Since volume is constant,
Hence $\frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{1}{3} = \frac{(273 + 30)}{T_{2}}$
$\Rightarrow T_{2} = 909K = 636℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.