Q. A cylinder of $5\ litre$ capacity, filled with air at N.T.P. is connected with another evacuated cylinder of $30\ litres$ of capacity. The resultant air pressure in both the cylinders will be
A) $38.85\ cm\ $of $Hg$
B) $21.85\ cm\ $of$\ Hg$
C) $10.85\ cm\ $of$\ Hg$
D) $14.85\ cm\ $of$\ Hg$
Explanation
(c) Here temperature remain constant
So $P_{1}V_{1} = P_{2}V_{2} \Rightarrow 76 \times 5 = P_{2} \times 35$
$\Rightarrow P_{2} = \frac{76 \times 5}{35} = 10.85cm\ of\ Hg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.