Q. A gas at the temperature $250\ K$ is contained in a closed vessel. If the gas is heated through $1K,$ then the percentage increase in its pressure will be
A) $0.4\%$
B) $0.2\%$
C) $0.1\%$
D) $0.8\%$
Explanation
(a) $P \propto T \Rightarrow \frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{P_{2} - P_{1}}{P_{1}} = \frac{T_{2} - T_{1}}{T_{1}}$
$\Rightarrow \left( \frac{\mathrm{\Delta}P}{P} \right)\% = \left( \frac{251 - 250}{250} \right) \times 100 = 0.4\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.