Q. What is the ratio of specific heats of constant pressure and constant volume for $NH_{3}$
A) 1.33
B) 1.44
C) 1.28
D) 1.67
Explanation
(a) For $NH_{3},$ degree of freedom $f = 6$
$\Rightarrow \frac{C_{P}}{C_{V}} = \gamma = 1 + \frac{2}{f} = 1 + \frac{2}{6} = \frac{4}{3} = 1.33$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.