Explanation

(b) The ideal gas law is the equation of state of an ideal gas. The state of an amount of gas is determined by its pressure, volume and temperature. The equation has the form
$pV = nRT$
where, $p$ is pressure, $V$ the volume, $n$ the number of moles, $R$ the gas constant and $T$ the temperature.
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \frac{p_{1}V_{1}}{T_{1}} = \frac{p_{2}V_{2}}{T_{2}}$
Given, $p_{1} = 200\ kPa,\ V_{1} = V,\ T_{1} = 273 + 22 = 295\ K,\ V_{2} = V + 0.02\ V$
$T_{2} = 273 + 42 = 315$ K
$\frac{200 \times V}{295} = \frac{p_{2} \times 1.02V}{315}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ p_{2} = \frac{200 \times 315}{295 \times 1.02}$
$p_{2} = 209\ $kPa