Q. At what temperature volume of an ideal gas at $0℃$ becomes triple
A) $546℃$
B) $182℃$
C) $819℃$
D) $646℃$
Explanation
(a) At sonstant pressure
$V \propto T \Rightarrow \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow T_{2} = \left( \frac{V_{2}}{V_{1}} \right)T_{1}$
$\Rightarrow T_{2} = \left( \frac{3V}{V} \right) \times 273 = 819K = 546℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.