Q. For a gas $\frac{R}{C_{V}} = 0.67.$ This gas is made up of molecules which are
A) Diatomic
B) Mixture of diatomic and polyatomic molecules
C) Monoatomic
D) Polyatomic
Explanation
(c) $C_{V} = \frac{R}{0.67} = 1.5R = \frac{3}{2}R$
This is the value for monoatomic gases
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.