Q. The translational kinetic energy of gas molecule for one mole of the gas is equal to
A) $\frac{3}{2}RT$
B) $\frac{2}{3}RT$
C) $\frac{1}{2}RT$
D) $\frac{2}{3}KT$
Explanation
(a) Kinetic energy for $1\ mole\ gas\ E = \frac{f}{2}RT$
$\Rightarrow E_{Translation} = \frac{3}{2}RT$
[$\because$ For all gases translational degree of freedom $f = 3$]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.