Q.
Graph between volume and temperature for a gas is shown in figure. If $\alpha =$ volume coefficient of gas $= \frac{1}{273}per℃,$ then what is the volume of gas at a temperature of $819℃$
A) $1 \times 10^{- 3}\ m^{3}$
B) $2 \times 10^{- 3}\ m^{3}$
C) $3 \times 10^{- 3}\ m^{3}$
D) $4 \times 10^{- 3}\ m^{3}$
Explanation
(b) $V_{t} = V_{0}(1 + \alpha t) = 0.5\left( 1 + \frac{1}{273} \times 819 \right) = 2\ litre = 2 \times 10^{- 3}m^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.