Q. A perfect gas at 27$℃$ is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be
A) 300$℃$
B) 54$℃$
C) 327$℃$
D) 600$℃$
Explanation
(a) $\frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$
$\frac{1}{2} = \frac{300}{T_{2}}$
$T_{2} = 600\ K = 600 - 273 = 327℃$
$\mathrm{\Delta}t = 327 - 27 = 300℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.