Q. The temperature of a gas at pressure $P$ and volume $V$ is $27℃.$ Keeping its volume constant if its temperature is raised to $927℃,$ then its pressure wil be
A) $2\ P$
B) $3\ P$
C) $4\ P$
D) $6\ P$
Explanation
(c) Using pressure or Gay-Lussac’s law $\frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}}$
or$\ P_{2} = \frac{P_{1}T_{2}}{T_{1}} = \frac{P(273 + 927)}{(273 + 27)} = 4P$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.