(a) $\frac{v_{2}}{v_{1}} = \sqrt{\frac{T_{2}}{T_{1}}} \Rightarrow \frac{v_{S}}{400} = \sqrt{\frac{(273 + 227)}{(273 + 27)}} = \sqrt{\frac{5}{3}}$ $\Rightarrow v_{s} = 400\sqrt{5/3} = 516m/s$
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Ph.D. in Physics with 19+ years of teaching experience.