(d) Pressure due to an ideal gas is given by
$p = \frac{M}{3V}v^{2}$
Putting $\frac{M}{V} = \rho,$ the density of gas
$p = \frac{1}{3}\rho v^{2}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = \sqrt{(\frac{3p}{\rho})}\ $
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v \propto \frac{1}{\sqrt{\rho}}$