When the temperature of a gas increases by 1$℃$, its pressure increases 0.4%. What is its initial temperature?

Question

Dr. Abubacker · Accepted Answer

(a) If the volume remains constant, then
$\frac{p_{1}}{p_{2}} = \frac{T_{1}}{T_{2}}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \frac{p}{p + \frac{0.4}{100}p} = \frac{T}{T + 1}$
$_{or}$ $T = 250$ $_{K}$

Q. When the temperature of a gas increases by 1$℃$, its pressure increases 0.4%. What is its initial temperature?

Explanation

Reviewed by Dr. Abubacker

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