Q. The molecular weight of a gas is 44. The volume occupied by $2.2\ g$ of this gas at $0℃$ and $2\ atm.$ pressure will be
A) $0.56\ litre$
B) $1.2\ litres$
C) $2.4\ litres$
D) $5.6\ litres$
Explanation
(a) $PV = mrT = m\left( \frac{R}{M} \right)T$
$\Rightarrow V = \left( \frac{m}{M} \right)\frac{RT}{P} = \left( \frac{2.2}{44} \right) \times \frac{8.31 \times (273 + 0)}{2 \times (1 \times 10^{5})}$
$= 5.67 \times 10^{- 4}m^{3} = 0.56$ litre
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.