(d) Average kinetic energy $\propto$ Temperature $\Rightarrow \frac{E_{1}}{E_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{100}{E_{2}} = \frac{300}{450} \Rightarrow E_{2} = 150J$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.