Q. The translatory kinetic energy of a gas per $g$ is
A) $\frac{3}{2}\frac{RT}{N}$
B) $\frac{3}{2}\frac{RT}{M}$
C) $\frac{3}{2}RT$
D) $\frac{3}{2}NKT$
Explanation
(b) Kinetic energy for $1g \Rightarrow E_{Trans} = \frac{3}{2}rT = \frac{3}{2}\frac{RT}{M}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.