Explanation

(a) Apparent weight $(w_{a})$= Actual weight $(w)$ $–\ upthrust\ (F),$ where upthrust = weight of water displaced = $V\ p\omega$ g
Now, $F_{0} = V_{0}\ \rho_{0}$ g and $F_{50} = V_{50}\ \rho_{50}$g
$\therefore\ \frac{F_{50}}{F_{0}} = \ \frac{V_{50}\ \rho_{50}\ g}{V_{0}\ \rho_{0}\ g\ } = \ \frac{1 + \gamma_{m} \times 50}{1 + \gamma_{w} \times 50}$
As $\gamma_{m} < \ \gamma_{w}$, therefore, $F_{50} < F_{0}$
Hence , $\left( w_{a} \right)_{50}\ \left( w_{a} \right)_{0}\ or\ w_{2} > w_{1}\ or\ \ w_{1} < w_{2}$