Q. If the internal energy of $n_{1}$ moles of He at temperature 10 T is equal to the internal energy of $n_{2}$ mole of hydrogen at temperature 6 T. the ratio of $\frac{n_{1}}{n_{2}}$ is
A) $\frac{3}{5}$
B) 2
C) 1
D) $\frac{5}{3}$
Explanation
(c) $n_{1}C_{v1}\mathrm{\Delta}T_{1} = n_{2}C_{v2}\mathrm{\Delta}T_{2}$
$\Rightarrow n_{1} \times \frac{3}{2}R \times 10 = n_{2} \times \frac{5}{2}R \times 6 \Rightarrow \frac{n_{1}}{n_{2}} = 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.