Q. If temperature of gas increases from $27℃$ to $927℃$ the $K.E.$ will be
A) Double
B) Half
C) One fourth
D) Four times
Explanation
(d) Kinetic energy $\propto$ Temperature
$\Rightarrow \frac{E_{1}}{E_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{E_{1}}{E_{2}} = \frac{(273 + 27)}{(273 + 927)} = \frac{300}{1200} = \frac{1}{4}$
$\Rightarrow E_{2} = 4E_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.