Q. What will be the force constant of the spring system shown in figure?

A) $\frac{k_{1}}{2} + k_{2}$
B) $\left\lbrack \frac{1}{2k_{1}} + \frac{1}{k_{2}} \right\rbrack^{- 1}$
C) $\frac{1}{2k_{1}} + \frac{1}{k_{2}}$
D) $\left\lbrack \frac{2}{k_{1}} + \frac{1}{k_{2}} \right\rbrack^{- 1}$
Explanation

(b) Two springs each of spring constant $k_{1}$ in parallel, given equailvalent spring constant of $2k_{1}$ and this is in series with spring of constant $k_{2}$, so equivalent spring constant,
$k = \left( \frac{1}{k_{2}} + \frac{1}{2k_{1}} \right)^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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