Q. A mass of $10\ kg$ is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes angle of $60{^\circ}$ with the vertical. The new reading of the balance is
A) $10\sqrt{3}\ kg\ wt$
B) $20\sqrt{3}kg\ wt$
C) $20\ kg\ wt$
D) $10\ kg\ wt$
Explanation
(c) [image:14_image52.emf]
$T\cos{60{^\circ} = 10}$
$T = \frac{10}{\cos{60{^\circ}}} = 20\ kgwt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.