
(c) [image:14_image53.emf]
As springs and supports ($M_{1}$ and $M_{2}$) are having negligible mass. Whenever springs pull the massless supports, springs will be in natural length. At maximum compression, velocity of $B$ will be zero
[image:14_image54.emf]
And by energy conservation
$\frac{1}{2}(4K)y^{2} = \frac{1}{2}Kx^{2} \Rightarrow \frac{y}{x} = \frac{1}{2}$