Q.
Two masses $m_{1}\ and\ m_{2}$ are suspended together
by a massless spring of constant $k$. When the
masses are in equilibrium, $m_{1}$ is removed without
disturbing the system. The amplitude of
oscillations is
A) $\frac{m_{1}g}{k}$
B) $\frac{m_{2}g}{k}$
C) $\frac{\left( m_{1} + m_{2} \right)g}{k}$
D) $\frac{\left( m_{1} - m_{2} \right)g}{k}$
Explanation
The correct answer is Option B: $\frac{m_{2}g}{k}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.