Q. The P.E. of a particle executing SHM at a distance $x$ from its equilibrium position is
A) $\frac{1}{2}m\omega^{2}x^{2}$
B) $\frac{1}{2}m\omega^{2}a^{2}$
C) $\frac{1}{2}m\omega^{2}(a^{2} - x^{2})$
D) Zero
Explanation
The correct answer is Option A: $\frac{1}{2}m\omega^{2}x^{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.