(a) $T = 2\pi\sqrt{\frac{m}{k}} \Rightarrow \frac{T_{2}}{T_{1}} = \sqrt{\frac{m_{2}}{m_{1}}} \Rightarrow \frac{3}{2} = \sqrt{\frac{m + 2}{m}} \Rightarrow \frac{9}{4} = \frac{m + 2}{m}$ $\Rightarrow m = \frac{8}{5}kg = 1.6\ kg$
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