Q. The maximum speed of a particle executing SHM is 1 $ms^{- 1}$ and maximum acceleration is 1.57 $ms^{- 2}.$ Its frequency is
A) 0.25 $s^{1}$
B) $2\ s^{1}$
C) $1.57\ s^{1}$
D) $2.57\ s^{1}$
Explanation
(a) $v_{0} = r\omega = 1$
And $a_{0} = \omega^{2}r = 1.57$
$\omega = \frac{\omega^{2}r}{r\omega} = 1.57/1$
Or $2\pi v = 1.57$
$v = \frac{1.57}{2 \times 3.14} = \frac{1}{4} = 0.25\ s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.