Q. The displacement of a particle executing SHM is given by y=0.25 sin 200t cm. the maximum speed of the particle is
A) $200\ cms^{- 1}$
B) $100\ cms^{- 1}$
C) $50\ cms^{- 1}$
D) $5.25\ cms^{- 1}$
Explanation
(c) $y = 0.25\sin{200t;}$
Speed, $\frac{dy}{dt} = 0.25 \times 200\cos{200t}$
Max. speed $= 0.25 \times 200 = 50\ cm\ s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.