Q. In a simple pendulum, the period of oscillation $T$ is related to length of the pendulum $l$ as

A) $\frac{l}{T} = constant$
B) $\frac{l^{2}}{T} = constant$
C) $\frac{l}{T^{2}} - constant$
D) $\frac{l^{2}}{T^{2}} = constant$
Explanation

(c) $T = 2\pi\sqrt{\frac{l}{g}} \Rightarrow \frac{l}{T^{2}} = \frac{g}{4\pi^{2}} = constant$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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