Q. A particle executes a simple harmonic motion of time period $T.$ Find the time taken by the particle to go directly from its mean position to half the amplitude
A) $T/2$
B) $T/4$
C) $T/8$
D) $T/12$
Explanation
(d) $y = A\sin{\omega t = \frac{A\sin{2\pi}}{T}t \Rightarrow \frac{A}{2} = A\sin{\frac{2\pi t}{T} \Rightarrow t = \frac{T}{12}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.