Q. The magnitude of maximum acceleration is $\pi$ times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is
A) 4
B) 2
C) 1
D) 0.5
Explanation
(b) Maximum acceleration = Maximum velocity$\times \pi$
$ie$, $\omega^{2}A = \pi\omega A$
where $A$ is amplitude and $\omega$ is angular velocity.
$\Rightarrow$ $\omega = \pi$
$\Rightarrow$ $\frac{2\pi}{T} = \pi$
$\Rightarrow$ $T = 2$ s
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.