Q. The angular velocities of three bodies in simple harmonic motion are $\omega_{1},\omega_{2},\omega_{3}$ with their respective amplitudes as $A_{1},A_{2},A_{3},.$ If all the bodies have same mass and velocity, then
A) $A_{1}\omega_{1} = A_{2}\omega_{2} = A_{3}\omega_{3}$
B) $A_{1}\omega_{1}^{\ \ 2} = A_{2}\omega_{2}^{\ \ 2} = A_{3}\omega_{3}^{\ \ 2}$
C) $A_{1}^{\ \ 2}\omega_{1} = A_{2}^{\ \ 2}\omega_{2} = A_{3}^{\ \ 2}\omega_{3}$
D) $A_{1}^{\ \ 2}\omega_{1}^{\ \ 2} = A_{2}^{\ \ 2}\omega_{2}^{\ \ 2} = A^{2}$
Explanation
(a) Velocity is same. So by using $v = a\omega$
$\Rightarrow A_{1}\omega_{1} = A_{2}\omega_{2} = A_{3}\omega_{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.